Download JEE Advanced 2025 Chemistry Question Paper - 1
SECTION 1 (Maximum Marks:12)
- This section contains FOUR (04) questions.
- Each question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is the correct answer.
- For each question, choose the option corresponding to the correct answer.
- Answer to each question will be evaluated according to the following marking scheme:
- Full Marks: +3 If ONLY the correct option is chosen;
- Zero Marks: 0 If none of the options is chosen (i.e. the question is unanswered);
- Negative Marks: -1 In all other cases.
- The heating of $NH_4NO_2$ at $60−70 °C$ and $NH_4NO_3$ at $200−250 °C$ is associated with the formation of nitrogen containing compounds $X$ and $Y$, respectively. $X$ and $Y$, respectively, are
- $N_2$ and $N_2O$
- $NH_3$ and $NO_2$
- $NO$ and $N_2O$
- $N_2$ and $NH_3$
- The correct order of the wavelength maxima of the absorption band in the ultraviolet-visible regionfor the given complexes is
- $[Co(CN)_6]^{3−}$ < $[Co(NH_3)_6]^{3+}$ < $[Co(NH_3)_5(H_2O)]^{3+}$ < $[Co(NH_3)_5(Cl)]^{2+}$
- $[Co(NH_3)_5(Cl)]^{2+}$ < $[Co(NH_3)_5(H_2O)]^{3+}$ < $[Co(NH_3)_6]^{3+}$ < $[Co(CN)_6]^{3−}$
- $[Co(CN)_6]^{3−}$ < $[Co(NH_3)_5(Cl)]^{2+}$ < $[Co(NH_3)_5(H_2O)]^{3+}$ < $[Co(NH_3)_6]^{3+}$
- $[Co(NH_3)_6]^{3+}$ < $[Co(CN)_6]^{3−}$ < $[Co(NH_3)_5(Cl)]^{2+}$ < $[Co(NH_3)_5(H_2O)]^{3+}$
- One of the products formed from the reaction of permanganate ion with iodide ion in neutral aqueous medium is
- $I_2$
- $IO_3^{-}$
- $IO_4^{-}$
- $IO_2^{-}$
- Consider the depicted hydrogen $(H)$ in the hydrocarbons given below. The most acidic hydrogen $(H)$ is
SECTION 2 (Maximum Marks:12)
- This section contains THREE (03) questions.
- Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these four option(s) is(are) correct answer(s).
- For each question, choose the option(s) corresponding to (all) the correct answer(s).
- Answer to each question will be evaluated according to the following marking scheme:
- Full Marks: +4 ONLY if (all) the correct option(s) is(are) chosen;
- Partial Marks: +3 If all the four options are correct but ONLY three options are chosen;
- Partial Marks: +2 If three or more options are correct but ONLY two options are chosen, both of which are correct;
- Partial Marks: +1 If two or more options are correct but ONLY one option is chosen and it is a correct option;
- Zero Marks: 0 If none of the options is chosen (i.e. the question is unanswered);
- Negative Marks: -2 In all other cases.
- For example, in a question, if (A), (B) and (D) are the ONLY three options corresponding to correct
answers, then
choosing ONLY (A), (B) and (D) will get +4 marks;
choosing ONLY (A) and (B) will get +2 marks;
choosing ONLY (A) and (D) will get +2 marks;
choosing ONLY (B) and (D) will get +2 marks;
choosing ONLY (A) will get +1 mark;
choosing ONLY (B) will get +1 mark;
choosing ONLY (D) will get +1 mark;
choosing no option (i.e. the question is unanswered) will get 0 marks; and choosing any other combination of options will get -2 marks.
- Regarding the molecular orbital $(MO)$ energy levels for homonuclear diatomic molecules, the INCORRECT statement(s) is(are)
- Bond order of $Ne_2$ is zero.
- The highest occupied molecular orbital (HOMO) of $F_2$ is σ-type.
- Bond energy of $O_2^{+}$ is smaller than the bond energy of $O_2$.
- Bond length of $Li_2$ is larger than the bond length of $B_2$.
- The pair(s) of diamagnetic ions is(are)
- $La^{3+}$, $Ce^{4+}$
- $Yb^{2+}$, $Lu^{3+}$
- $La^{2+}$, $Ce^{3+}$
- $Yb^{3+}$, $Lu^{2+}$
- For the reaction sequence given below, the correct statement(s) is(are)
(In the options, X is any atom other than carbon and hydrogen, and it is different in P, Q and R)- C−X bond length in P, Q and R follows the order Q > R > P.
- C−X bond enthalpy in P, Q and R follows the order R > P > Q.
- Relative reactivity toward SN2 reaction in P, Q and R follows the order P > R > Q.
- pKa value of the conjugate acids of the leaving groups in P, Q and R follows the order R > Q > P.
SECTION 3 (Maximum Marks:24)
- This section contains SIX (06) questions.
- The answer to each question is a NON-NEGATIVE INTEGER.
- For each question, enter the correct integer corresponding to the answer using the mouse and the on- screen virtual numeric keypad in the place designated to enter the answer.
- Answer to each question will be evaluated according to the following marking scheme:
- Full Marks: +4 If ONLY the correct integer is entered;
- Zero Marks: 0 In all other cases.
- In an electrochemical cell, dichromate ions in aqueous acidic medium are reduced to $Cr^{3+}$. The current (in amperes) that flows through the cell for 48.25 minutes to produce 1 mole of $Cr^{3+}$ is ______.
Use: 1 Faraday = 96500 $C mol^{−1}$ - At 25 ℃, the concentration of $H^{+}$
ions in $1.00 × 10^{−3} M$ aqueous solution of a weak monobasic acid having acid dissociation constant $(K_a)$ of $4.00 × 10^{−11}$ is $𝑿 × 10^{−7} M$. The value of $𝑿$ is ______.
Use: Ionic product of water $(K_w)$ = $1.00 × 10^{−14}$ at 25 ℃ - Molar volume $(V_m)$ of a van der Waals gas can be calculated by expressing the van der Waals equation as a cubic equation with $V_m$ as the variable. The ratio (in $mol dm^{−3}$) of the coefficient of $𝑉_m^2$to the coefficient of $V_m$ for a gas having van der Waals constants $a = 6.0 dm^6 atm mol^{−2}$
and $b = 0.060dm^3 mol^{−1}$ at 300 $K$ and 300 $atm$ is ______.
Use: Universal gas constant $(R)$ = $0.082 dm^3 atm mol^{−1} K^{−1}$ - Considering ideal gas behavior, the expansion work done (in $kJ$) when $144 g$ of water is electrolyzed completely under constant pressure at $300 K$ is ______.
Use: Universal gas constant ($R$) = $8.3 J K^{−1} mol^{−1}$; Atomic mass (in $amu$): $H$ = 1, $O$ = 16 - The monomer $(X)$ involved in the synthesis of Nylon 6,6 gives positive carbylamine test. If 10 moles of $X$ are analyzed using Dumas method, the amount (in grams) of nitrogen gas evolved is ______.
Use: Atomic mass of $N$ (in $amu$) = 14 - The reaction sequence given below is carried out with 16 moles of $X$. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of $S$produced is______.
Use: Atomic mass (in $amu$): $H$ = 1, $C$ = 12, $O$ = 16, $Br$ = 80
SECTION 4 (Maximum Marks:12)
- This section contains FOUR (04) Matching List Sets.
- Each set has ONE Multiple Choice Question.
- Each set has TWO lists: List-I and List-II.
- List-I has Four entries (P), (Q), (R) and (S) and List-II has Five entries (1), (2), (3), (4) and (5).
- FOUR options are given in each Multiple Choice Question based on List-I and List-II and ONLY ONE of these four options satisfies the condition asked in the Multiple Choice Question.
- Answer to each question will be evaluated according to the following marking scheme:
- Full Marks: +3 ONLY if the option corresponding to the correct combination is chosen;
- Zero Marks: 0 If none of the options is chosen (i.e. the question is unanswered);
- Negative Marks: -1 In all other cases.
- The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is
List - I List - II (P) Passing $H_2S$ in the presence of $NH_4OH$ (1) $Cu^{2+}$ (Q) $(NH_4)_2CO_3$ in the presence of $NH_4OH$ (2) $Al^{3+}$ (R) $NH_4OH$ in the presence of $NH_4Cl$ (3) $Mn^{2+}$ (S) Passing $H_2S$ in the presence of dilute $HCl$ (4) $Ba^{2+}$ (5) $Mg^{2+}$
The correct option is:- P → 3; Q → 4; R → 2; S → 1
- P → 4; Q → 2; R → 3; S → 1
- P → 3; Q → 4; R → 1; S → 5
- P → 5; Q → 3; R → 2; S → 4
-
The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.
List - I List - II (P) Stephen reaction (1) (Q) Sandmeyer reaction (2) (R) Hoffmann bromamide degradation reaction (3) (S) Cannizzaro reaction (4) (5)
The correct option is:- P → 2; Q → 4; R → 1; S → 3
- P → 2; Q → 3; R → 4; S → 1
- P → 5; Q → 3; R → 4; S → 2
- P → 5; Q → 4; R → 2; S → 1
-
Match the compounds in List-I with the appropriate observations in List-II and choose the correct option.
List - I List - II (P) (1) Reaction with phenyl diazonium salt gives yellow dye. (Q) (2) Reaction with ninhydrin gives purple color and it also reacts with $FeCl_3$ to give violet color. (R) (3) Reaction with glucose will give corresponding hydrazone. (S) (4) Lassiagne extract of the compound treated with dilute $HCl$ followed by addition of aqueous $FeCl_3$ gives blood red color. (5) After complete hydrolysis, it will give ninhydrin test and it DOES NOT give positive phthalein dye test.
The correct option is:- P → 1; Q → 5; R → 4; S → 2
- P → 2; Q → 5; R → 1; S → 3
- P → 5; Q → 2; R → 1; S → 4
- P → 2; Q → 1; R → 5; S → 3
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